Răspuns:
Explicație pas cu pas:
f(3)=0
f(0)=[tex]\frac{1}{2}[/tex]
[tex]f(3)=\frac{9m^{2} -3(m+1)+1}{9+n} =0\\\\\\f(0)=\frac{1}{n} =\frac{1}{2}[/tex]
n=2
[tex]f(3)=\frac{9m^{2} -3(m+1)+1}{9+2} =0\\[/tex]
9m²-3m-3+1=0
9m²-3m-2=0
Δ=9+72=81
[tex]m_{1}=\frac{3+9}{18} =\frac{2}{3} \\\\\\m_{2}=\frac{3-9}{18}=-\frac{1}{3} \\\\\\[/tex]
