Răspuns:
a) 5(3x-2)-6(8x-13)-13x=16(8-3x)-62
15x-10-48x+78-13x=128-48x-62
-48 x din dreapta se reduce cu -48 din stanga
si atunci ramane:
2x-68=128-62
2x=128-62+68
2x= 66+68
2x= 134
x= 134:2
x= 67
b) 2(3x-4)+5(6x-7)-7x=16(x+15)-10
6x-8+30x-35-7x=16x+240-10
29x-43=16x+230
29x-16x=230+43
13x=273
x=273:13
x=21