Explicație pas cu pas:
[tex]x = \sqrt{2} + \frac{1}{ \sqrt{2}} = \frac{ \sqrt{2} \times \sqrt{2} + 1}{ \sqrt{2} } = \frac{2 + 1}{ \sqrt{2} } \\ = > x = \frac{3}{ \sqrt{2} } \\ y = \sqrt{2} [/tex]
[tex]\frac{x}{y} = \frac{ \frac{3}{ \sqrt{2} } }{ \sqrt{2} } = \frac{3}{ \sqrt{2} \times \sqrt{2} } = \frac{3}{2} \\ [/tex]
sau:
[tex]x = \frac{ \sqrt{2} + 1}{ \sqrt{2}} \\ y = \sqrt{2} [/tex]
[tex] \frac{x}{y} = \frac{ \frac{ \sqrt{2} +1}{ \sqrt{2} } }{ \sqrt{2} } = \frac{ \sqrt{2} + 1}{ \sqrt{2} \times \sqrt{2} } = \frac{ \sqrt{2} + 1}{2} \\ [/tex]
