Explicație pas cu pas:
teorema sinusurilor:
[tex]\frac{AC}{ \sin(B) } = \frac{AB}{ \sin(C) } \\ \frac{AB}{AC} = \frac{ \sin( \frac{\pi}{4} ) }{ \sin( \frac{\pi}{3} ) } = \frac{ \sin(45) }{ \sin(60) } = \frac{ \frac{ \sqrt{2} }{2} }{ \frac{ \sqrt{3} }{2} } = \frac{ \sqrt{2} }{ \sqrt{3} } \\ = > \frac{AB}{AC} = \frac{ \sqrt{6} }{3} [/tex]
