Explicație pas cu pas:
b)
[tex]\left[0,(3) + \left(\frac{1}{3} \right)^{2} \right] \cdot 1,5 = \left(\frac{3}{9} + \frac{1}{9} \right) \cdot \frac{15}{10} \\ = \frac{4}{9}\cdot \frac{3}{2} = \frac{2}{3} [/tex]
c)
[tex]0,8(3):2,(3)\cdot \left(1+ \frac{1}{2} \cdot \frac{1}{3} \right) = \\ = \frac{83 - 8}{90}: \frac{23 - 2}{9}\cdot \left( \frac{6}{6} + \frac{1}{6}\right) \\ = \frac{75}{90}: \frac{21}{9}\cdot \frac{7}{6} = \frac{5}{6} \cdot \frac{3}{7}\cdot \frac{7}{6} = \frac{5}{12}[/tex]
